Algorithm/CodeUp
1270 : 1의 개수는? 1
B2SIC
2020. 4. 10. 03:57
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 | #include <stdio.h> int main(void) { // 1 11 21 31 ... 91 101 111 121 131 ... 991 1001 1011 (등차수열) int i, n; int count = 0; scanf("%d", &n); for(i = 1; i <= n; i += 10) count++; printf("%d", count); return 0; } | cs |